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10^x=1/x
We move all terms to the left:
10^x-(1/x)=0
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
10^x-(+1/x)=0
We get rid of parentheses
10^x-1/x=0
We multiply all the terms by the denominator
10^x*x-1=0
Wy multiply elements
10x^2-1=0
a = 10; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·10·(-1)
Δ = 40
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{40}=\sqrt{4*10}=\sqrt{4}*\sqrt{10}=2\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{10}}{2*10}=\frac{0-2\sqrt{10}}{20} =-\frac{2\sqrt{10}}{20} =-\frac{\sqrt{10}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{10}}{2*10}=\frac{0+2\sqrt{10}}{20} =\frac{2\sqrt{10}}{20} =\frac{\sqrt{10}}{10} $
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